2.) Hydrogen have to be bonded to a highly electronegative facet which are nitrogen ($\ceN$), fluorine ($\ceF$) and also oxygen ($\ceO$).
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Seeing that both oxygen and also chlorine have a small difference in your electronegativity (oxygen being about 3.5 and chlorine being about 3.0), why does chlorine in a hydrogen chloride molecule ($\ceHCl$) have actually a dipole-dipole interaction, if the oxygen in a water molecule ($\ceH2O$) causes the water molecule to have a stronger kind of dipole-dipole interaction called hydrogen bonding? I execute not know this since chlorine is simply as electronegative as oxygen and also nitrogen?
Edit: I should also included that nitrogen and chlorine have the exact same EN value (3.0)
electronegativity dipole hydrogen-bond
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edited Jun 11 "20 in ~ 10:20
asked may 17 "15 at 16:49
louis AverhoffLuis Averhoff
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Well, first-of-all you require to know that the $\ceH$ bonding isn"t in reality bonding. That is simply a covalent attraction. Additionally since $\ceCl$ is larger than $\ceN$, $\ceF$ and also $\ceO$ that does not make a solid $\ceH$ bond. The size of the $\ceCl$ renders the dipole-dipole attraction weaker. However $\ceN$, $\ceF$ and also $\ceO$ are smaller and thus have actually an $\ceH$ bond.
Although in reality, contrasted to various other covalently bonded structures, $\ceHCl$ has actually a very strong covalent bond.
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answered may 17 "15 at 17:23
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Despite that is electronegativity, size of chlorine atom is huge and hence, electron thickness of chlorine is not sufficient to form Hydrogen Bonding.Hence, HCl walk not have actually hydrogen Bonding.
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answered jan 6 "18 at 10:03
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