2.) Hydrogen have to be bonded to a highly electronegative facet which are nitrogen ($\ceN$), fluorine ($\ceF$) and also oxygen ($\ceO$).

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Seeing that both oxygen and also chlorine have a small difference in your electronegativity (oxygen being about 3.5 and chlorine being about 3.0), why does chlorine in a hydrogen chloride molecule ($\ceHCl$) have actually a dipole-dipole interaction, if the oxygen in a water molecule ($\ceH2O$) causes the water molecule to have a stronger kind of dipole-dipole interaction called hydrogen bonding? I execute not know this since chlorine is simply as electronegative as oxygen and also nitrogen?

Edit: I should also included that nitrogen and chlorine have the exact same EN value (3.0)


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louis AverhoffLuis Averhoff
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Very, really related. Check it for a more in depth answer.

Well, first-of-all you require to know that the $\ceH$ bonding isn"t in reality bonding. That is simply a covalent attraction. Additionally since $\ceCl$ is larger than $\ceN$, $\ceF$ and also $\ceO$ that does not make a solid $\ceH$ bond. The size of the $\ceCl$ renders the dipole-dipole attraction weaker. However $\ceN$, $\ceF$ and also $\ceO$ are smaller and thus have actually an $\ceH$ bond.

Although in reality, contrasted to various other covalently bonded structures, $\ceHCl$ has actually a very strong covalent bond.


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answered may 17 "15 at 17:23
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Despite that is electronegativity, size of chlorine atom is huge and hence, electron thickness of chlorine is not sufficient to form Hydrogen Bonding.Hence, HCl walk not have actually hydrogen Bonding.

See more: What Episode Does Sakura Kiss Naruto ? Does Naruto Kiss Sakura


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answered jan 6 "18 at 10:03
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