5.43 x 10^-3 Nm
N = 52.5, radius, r = 5.35 cm = 0.0535 m, B = 0.455 T, I = 25.3 mA = 0.0253 A
Torque = N I A B Sin theta
Here, theta = 90 degree
Torque = 52.5 x 0.0253 x 3.14 x 0.0535 x 0.0535 x 0.455
Torque = 5.43 x 10^-3 Nm
175 N to the right
I am taking the quiz and this is the correct beer-selection.com. The pedaling force if 250 N but when it encounters 75 N of air resistance, it reduces to 175 N. This is because the air resistance is going opposite of you.
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Based on Newton’s 3rd Law of motion, if an archer shoots an arrow at the target, the action force is the bowstring against the a
beer-selection.com: the reaction force is the arrows push against the bow sting
Explanation:the two objects must react the very same , bowstring and arrow.
Light of intensity I0 and polarized horizontally passes through three polarizes. The first and third polarizing axes are horizon
Suppose that we have light polarized in some given direction with an intensity I0, and it passes through a polarizer that has an angle θ with respect to the polarization of the light, the intensity that comes out of the polarizer will be:
I(θ) = I0*cos^2(θ)
Ok, we know that the light is polarized horizontally and comes with an intensity I0
The first polarizer axis is horizontal, then the intensity after this polarizer is:
then θ = 0°
I(0°) = I0*cos^2(0°) = I0
The intensity does not change. The axis of polarization does not change.
The second polarizer is oriented at 20° from the horizontal, then the intensity that comes out of this polarizer is:
I(20°) = I0*cos^2(20°) = I0*0.88
And the axis of polarization of the light that comes out is now 20° from the horizontal
Now the light passes through the last polarizer, which has an axis oriented horizontally, so the final intensity of the light will be:
note that here the initial polarization is I0*0.88
and the angle between the axis is 20° again.
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Then the final intensity is:
I(20°) = I0*0.88*cos^2(20°) = I0*0.78
Then the correct option is C.
beer-selection.com: the falling time
When a body or object falls, basically two forces act on it:
1. The force of air friction, also called "drag force"
So, this force is proportional to the transversal area of the falling element and to the square of the velocity.
2. Its weight due to the gravity force
So, at the moment when the drag force equals the gravity force, the object will have its terminal velocity: