Rewrite the square root of the division frac81100 as the division of square roots fracsqrt81sqrt100. Take the square root of both numerator and denominator.

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displaystylefrac32 Explanation:If you recognise 81 and 16 as being 4th powers, the answer is easy to write down asdisplaystylefrac32 Otherwise write each number as ns ...
displaystylefracsqrt81121=frac9121 Explanation:Simplify:displaystylefracsqrt81121 By definition, the square root of 81 is 9.displaystylefracsqrt81121=frac9121
The result isdisplaystyle-frac94 .Explanation:You can distribute the radical onto each of the fraction parts, then simplify each one: displaystyle=-sqrtfrac8116 ...
displaystylefrac913 Explanation:We can use the principle thatdisplaystylesqrtfracab=fracsqrtasqrtb : displaystylesqrtfrac81169=fracsqrt81sqrt169=frac913
See a solution process below:Explanation:First, using this rule of radicals rewrite the expression: displaystylesqrtfracab=fracsqrtleft(a ight)sqrtleft(b ight) ...
https://stats.stackexchange.com/questions/212758/distribution-of-posterior-mean-from-different-datasets
I interpret your code as follows: For B = 1, 2, dots 100 (i) Generate y sim N(1_n, I_n) (ii) Generate X mid y sim N(1_r ^-1nary, ^-1I_r) (iii) Compute and store arX = 1_r'X/r ...

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Rewrite the square root of the division frac81100 as the division of square roots fracsqrt81sqrt100. Take the square root of both numerator and denominator.
left< eginarray l l 2 & 3 \ 5 & 4 endarray ight> left< eginarray l l l 2 & 0 & 3 \ -1 & 1 & 5 endarray ight>
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