You are watching: A mixture containing 9 mol of f2
A mixture include 9 mol of F2 and also 4 mol of S is allowed to react. 3 F2 + S -> SF6 how many moles that F2 remain after 3 mol of S have actually reacted? i believe the prize is zero yet can anyone describe why the answer states 1
ns would also say Zero. Perhaps the answer key is wrong? 3 moles of F2 react with 1 Mole that S to do 1 Mole of product. If 3 mole of S reacts..it would require 9 mole of F2, leaving zero left over. Overall, you would be left with 1 mole of S the didn"t partake in the reaction.
ns would likewise say Zero. Maybe the answer vital is wrong? 3 mole of F2 react with 1 Mole that S to make 1 Mole of product. If 3 moles of S reacts..it would require 9 mole of F2, leaving zero left over. Overall, you would be left v 1 mole the S that didn"t partake in the reaction.
ns agree.. An easy ques. Wonder why it would certainly say 1 mol of F2 left over. What book is this inquiry from?
3F2 + 1S --> SF6 9F2 + 4S --> 3SF6 F = 18 on left side and right side S = 4 ~ above left yet only 3 on best side Is that just how there is one mole of miscellaneous left over?
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