displaystyle12a^2+36ab+27b^2 Explanation:Multiply each term that the first binomial by each term the the 2nd binomial. In other words, multiply 2a by 6a, 2a by 9b, 3b by ...

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6a2-5ab-4b Final an outcome : 6a2 - 5ab - 4b Reformatting the input : changes made to her input have to not impact the solution: (1): "a2" was changed by "a^2". Step by step solution : step 1 ...
just how do you solve the system of equations displaystyle2a-5b=-19 and displaystyle3a+5b=9 ?
displaystylea=-2anddisplaystyleb=3 .Explanation:We have two equationsdisplaystyle2a-5b=-19anddisplaystyle3a+5b=9 .It is listed that coefficients ...
how do you multiply displaystyleleft(3-5i ight)left(1-16i ight) in trigonometric form?
displaystyleleft(left(-3-5i ight)cdotleft(1-16i ight)approx-0.323+i0.1673 ight. Explanation:To dividedisplaystyleleft(-3-5i ight)cdotleft(1-16i ight) ...

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Alan P. May 23, 2015displaystyleleft(ab+2a ight)+left(3b+6 ight)displaystyle=left(aleft(b+2 ight) ight)+left(3left(b+2 ight) ight) ...
in order come multiply we multiply an initial term that the very first bracket with the whole 2nd bracket and same with the 2nd numberExplanation: displaystyleleft(2a+3b ight)left(5c+7d ight)=2aleft(5c+7d ight)+3bleft(5c+7d ight)=10ac+14ad+15bc+21bd
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left< eginarray l l 2 & 3 \ 5 & 4 endarray ight> left< eginarray together l l 2 & 0 & 3 \ -1 & 1 & 5 endarray ight>

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